When it comes to the best takeout New Year's Eve parties in the East Bay, Spicy Hideaway is definitely the place to go.
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'We handle all parts of your cocktail party,' owner Noel Crist told Berkeleyside of Spicy Hideaway's Chinatown location, which is closed for the holidays.
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A 'proper New Year's Eve,' Crist said, 'is when we take you out to a fun dinner at a nice neighborhood restaurant.' Stronghold crusader 2 download free. full game pc.
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Perfect for the first few hours of 2019, Spicy Hideaway serves a light, yet reasonably priced first course such as braised short ribs that's seasoned with fresh, wild mushrooms.
The second course is a traditional Chinese New Year's offering called scallion soup with red pepper vinaigrette served over steamed rice.
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Pro tip: Spicy Hideaway's takeout takeout party is not only fast — it's heavily recommended because of the 20 cocktails Crist mentions before the crew settles down to a fitting meal. If you're truly looking to impress a friend with your revelry, Crist said that his takeout-only restaurant has a couple of hot takeout spots that are always hopping — Jello Man, 112th Street and Bathulia, for example, that do a couple of two-hour pizzas on New Year's Eve.
More of an extravaganza for the partygoing doyenne in the East Bay, Spicy Hideaway's New Year's Eve event is happening Friday, Dec. 28. Can you download fortnite on a dell computer. And like anything else, there are some logistical and financial issues to consider. To be fair, Crist insisted, his New Year's Eve event is 'uncomfortable.'
Pubg game download for windows 7. 'The only thing you can do is come in early and we will take over,' he said. 'We will take over the drinks, appetizers, new gala table and a big party room.'
Spicy Hideaway has a real mission of celebrating Chinese New Year: 'We are here to honor, thank and cherish our first year,' Crist said. 'Hopefully in 2018 we'll have another fruitful year.'
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def checkio(data):
'Return True if password strong and False if not'
num = False
upper = False
lower = False
for i in range(len(data)):
num = num or data[i].isnumeric()
upper = upper or data[i].isupper()
lower = lower or data[i].islower()
return num and upper and lower and len(data)>=10
This is a perfectly acceptable solution for passwords, which are typically not very long. I am going to give you some advice on how to make the function faster, but realize that in practice you won't be able to measure the speedup, unless you are calling this function (and nothing else) millions of times for different strings.
A general trick for making validation functions fast is to test for the easy conditions first. In this case, if the data is too short, you'd be wasting time in the for-loop. In Python you are allowed to have multiple return statements per function, so you could add this to the top of your function:
if len(data) < 10:
return False
Then you can replace the final return with
return num and upper and lower
Next, you are not using all the conveniences of the for-loop! Instead of writing
for i in range(len(data)):
and then using data[i] in the body of the loop three times, you can iterate over the characters of the input string directoy:
for char in data:
and then in the body, use char instead of data[i].
